Need to get specific part of URL

Product Forums Katalon Studio
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1

Hello Team,

I need one help. I need to save one specific part of URL

This is the URL

https://this-is-my-url.com/24160553/checkouts/1209280661348825c36174f4f3bdce1b/thank_you

And want to extract

1209280661348825c36174f4f3bdce1b

and save it to url.

2

If the URL will always be the same size, then you can parse it using the “substring(startPosition, endPosition)” function, such as myUrl.substring(47, 79).

def myUrl = WebUI.getUrl()
def myContents = myUrl.substring(47, 79)
WebUI.comment("your contents are ${myContents}")

If the URL may not always be the same size, then you can try parsing it with the split("/") function, such as myUrl.split("/")[5]

def myUrl = WebUI.getUrl()
def myContents = myUrl.split("/")[5]
WebUI.comment("your contents are ${myContents}")

the 5 means we want the 6th item of the array that the split() creates (I think it’s the sixth we want) because the counting of arrays starts at zero.

2 Likes
3

Code

URL url = new URL("https://this-is-my-url.com/24160553/checkouts/1209280661348825c36174f4f3bdce1b/thank_you")
String path = url.getPath()   
println path                  //    /24160553/checkouts/1209280661348825c36174f4f3bdce1b/thank_you

List elements = path.split("/") as List
elements.eachWithIndex({ e, index ->
	println "${index} ${e}"
})
println "wanted: " + elements[3]

Output

0 
1 24160553
2 checkouts
3 1209280661348825c36174f4f3bdce1b
4 thank_you
wanted: 1209280661348825c36174f4f3bdce1b
1 Like